Help with classes

I'm learning how to make classes in school and everything works fine and dandy over there but when I try to make classes at home and use them at my house i get an error

cannot find symbol constructor EmployeeGriggs(java.lang.String,int)

I have saved both files and they are in the same folder if that even matters any help?

Please post the code so we can see where the problem is. Remember to wrap the text that has code section using the "CODE Tag" (third icon above from right to left).
CJSL

This is the class

Code:

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/**
 *Chris Griggs
 *October 9
 */


public class EmployeeGriggs {

public String Employee;//These two variables can be used by all the methods
public Double Salary;

    public void EmployeeGriggs(String EmployeeName, Double CurrentSalary) {
           
            Employee = EmployeeName;//takes the employees name and puts into the employee variable for use by the methods
            Salary = CurrentSalary;//takes the salary and puts in the salary  variable for use by the methods
           
    }
   
    public String GetName(){
            return Employee;//sends out whatever is in the variable at the time when called on
    }
   
    public double GetSalary(){
            return Salary;//sends out whatever is in the variable at the time when called on
    }
   
    public void raiseSalary(double percent){
            percent = percent/100; //divides the variabe percent by a hundred to make it into a decimal
            double NewSalary = Salary * percent;//creates a new variable and finds how much the increase will be
            Salary = NewSalary * Salary;//adds the increase and current salary together
    }
}

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This is the driver

Code:

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/**
 *Chris Griggs
 *October 9
 */

public class EmployeeTesterGriggs
{
        public static void main(String[] args)
        {
                EmployeeGriggs harry = new EmployeeGriggs("Harry Hacker", 50000);//intializes the EmployeeGriggs class
                harry.raiseSalary(10);//Raises the salary by 10 percent
                System.out.println(harry.GetName());//Calls on GetName to get a name
                System.out.println(harry.GetSalary());//Calls on GetSalary to get a salary
        }
}

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Where is the error message? It has the source line number and text.

What are the types of args to the Constructor?
what types are you passing to the constructor?
Hint: 50000 is not a Double.

this:

Code:

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public void EmployeeGriggs(String EmployeeName, Double CurrentSalary)

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is not a constructor as it has a return type of "void". A true constructor has no return type. So try removing the void and see what happens.

Quote:

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Originally Posted by Norm

Hint: 50000 is not a Double.

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I don't think that this will matter as Java will convert this number to double without much trouble. There's a name for this process, but it escapes me.

Fubarable - I think you may mean casting

I did take out the void and still the same error

"cannot find symbol constructor EmployeeGriggs(java.lang.String,int)"

it is also at line 10, could there be a problem with the IDE (JCreator) that I need to do something in the options?

Could it be that you're calling the class with the wrong type arguments? The second argument of your class has an int when it should be a double.
CJSL

Ok well I changed 50000 to 50000.0 because it has a decimal point and it compiles and runs but when I call for the salary its kinda ridiculous and comes out at 2.5E8

Try 50000.0

OOOOO that problem may have something to do with the salary but that's a different problem. Thanks for the help guys.

It is better to use interger data types for money to prevent rounding errors. However for student exercises it doesn't matter.

Add some println() statements to the raise method to show intermediate values so you'll know what your code is doing.\

Quote:

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Salary = NewSalary * Salary;//adds ...

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Reading the coment looks like this is the problem

Quote:

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Originally Posted by gnarly hogie

Fubarable - I think you may mean casting

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OK, it's actually called "implicit casting" and should cause no problem. The allowable implicit casts are: byte or char → short → int → long → float → double.

Again, so using an int as a parameter value will cause no problem.

for any non-believers:

Code:

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public class ImplicitCast
{
  public ImplicitCast(double myDouble)
  {
    System.out.println("this works as myDouble has been automatically implicitly cast: " + myDouble);
  }
 
  public static void main(String[] args)
  {
    ImplicitCast myObj = new ImplicitCast(5000);
  }
}

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Okie dokie then now all is well thanks.

The arg was Double not double. Here's what I see:

Code:

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public class TestCast {
        public static void method(Double d) {
                // code
        }
        public static void main(String[] args) {
                TestCast.method(1);
        }
}/*Running: C:\Program Files\Java\jdk1.5.0_04\bin\javac.exe -cp D:\JavaDevelopment\Testing\JavaForum\;D:\JavaDevelopment -deprecation -g -Xlint TestCast.java

TestCast.java:6: method(java.lang.Double) in TestCast cannot be applied to (int)
                TestCast.method(1);
                        ^
1 error
Running: D:\Java\jdk1.6.0_02\bin\javac.exe -Xlint -g -deprecation -classpath D:\JavaDevelopment\;. D:\JavaDevelopment\Testing\JavaForum\TestCast.java

D:\JavaDevelopment\Testing\JavaForum\TestCast.java:6: method(java.lang.Double) in TestCast cannot be applied to (int)
                TestCast.method(1);
                        ^
1 error

*/

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