Calculate what e1 and e2 should be

[Legoland]

Hi!
I hope someone can help me out.
If e1 has value 5 and e2 has value 8 before this lines has been executed:
int t = e1;
e1 = e2;
e2 = t;
what value will e1 and e2 has after that.
I have started like this: mport javax.swing.*;

public class Tilldelning2 {
public static void main (String[] arg) {
int e1 = 5;
int e2 = 8;
int t = e1;
e1 = e2;
e2 = t;
JOptionPane.MessageDialog(null, "e1 =" + t +" e2");
System.exit(0);
}
}

Thanks for help in advance Legoland,

[pegitha]

I am not sure I am understanding your question. e1 will still =8 and e2 will still =5.
However, I cannot compile this code because it fails on the
"JOptionPane.MessageDialog". I do not find any static method called
MessageDialog in JOptionPane. Maybe I am using a different version of java than you. I am still on 5.0.
p

[Legoland]

hi!
Yes e1 will still have value 5 and e2 will have value 8. Maybe I have another version of Java than you.
Legoland

[pegitha]

If I use JOptionPane.showMessageDialog(null, "e1 =" + t +" e2");
then what popup is:
e1=5 e2
Is that your question?

[Legoland]

Yes
it helped me a bit on the way I must have missed to write show before message in JOptionPane.....
anyway now I have to figure out how to get the new value into e2 i think the message to the suser should be something like e1= 5 e2=... and then some value.

[goldhouse]

This is one of the tricky question often asked in interviews.
The result for the below will be

Code:

int a =5, b =8;
temp = a;
a = b;
b = temp;
System.out.println("a = " + a + " b = " + b) // give result a=8 b =5

The above code swapped the variable values , Now the question is how can we achieve this without using the temp.

Code:

int double =5,double = 8;
a = a + b;
b = a -b;
a = (a - b) /2 ;
System.out.println("a = " + a + " b = " + b) // give result a=8 b =5

I like somebody to explain the below code.

[Legoland]

Hello!
If e1 = 5 and e2 = 8 before the following lines has been executed what values will they have afterwards.
The lines are: int t = e1;
e1 = e2;
e2 = t;

Create a program that shows the new values of e1 and e2

I hope I have exlained this correctly.
Regards Legoland

[goldhouse]

[levent]

Quote:

Hello!
If e1 = 5 and e2 = 8 before the following lines has been executed what values will they have afterwards.
The lines are: int t = e1;
e1 = e2;
e2 = t;

Create a program that shows the new values of e1 and e2

Your code should work. What is the problem?

[Legoland]

Hi!
When I runs the program I get the result e1=55 but I don´t get a value for e2
Legoland

[Legoland]

Hi!
I have created new program it looks like this:
import javax.swing.*;

public class Tilldelning4 {
public static void main (String[] arg) {
int e1 = 5;
int e2 = 8;
int t = e1;
e1 = e2;
e2 = t;
JOptionPane.showMessageDialog(null, "e1 =" + t + e2 + " e2=" + e2 + t + e1 );
System.exit(0);

}
}
When I run the program I get e1= 55 and e2= 558
How can I make sure that i have the right result??
Legoland

[olatunbode]

when you concatenate using a string and some other variables, all the values are concatenated together, so if a = 5 and b = 6, the output of the code:

System.out.println("The values are: " + a + b);

would be: The values are: 56

That is because it converts the primitives a and b to strings and concatenates them together. If u want a and b to be added, this will to it:

System.out.println("The values are: " + (a + b));

This is becos parenthesis takes precedence anywhere!

But if u want the two values to be displayed 'as is', you have to put a space btw them i.e

System.out.println("The values are: " + a + " " + b);

Take care!