seperation of file contents

[Ms.Ranjan]

hi
i need some logic to solve a problem there are two array list.i have to compare the two array list and write the similar lines in both list and non similar lines in both the list in two separate files.

list 1 contains these lines from a file
ename eid evalue
S 01 S425
P 02 P637
C 03 C826

list2 contains these lines from another file
ename eid evalue
P 02 P637
E 04 E738
D 05 D369

the o/p file that should contain similar one should have
ename eid evalue
P 02 P637

the o/p file that should contain dissimilar ones should have
ename eid evalue
S 01 S425
C 03 C826
E 04 E738
D 05 D369

and how do i go about having "ename eid evalue" in both the files..

any suggestions please..

[Ms.Ranjan]

The code which i have tried is here:

import java.io.*;
import java.util.*;

class comparef1
{
   public static void main(String args[])throws IOException
   {
     try{
     String line1;
     String line2;
     ArrayList<String> list1=new ArrayList<String>();
     ArrayList<String> list2=new ArrayList<String>();
     ArrayList<String> list_similar=new ArrayList<String>();
     ArrayList<String> list_disimilar=new ArrayList<String>();
     
     		BufferedReader br1=new BufferedReader(new FileReader("File1.txt"));
      		while((line1=br1.readLine())!=null)
       		{
         	list1.add(line1);
                //System.out.println(list1);
          	}
                
                
     		BufferedReader br2=new BufferedReader(new FileReader("File2.txt"));
      		while((line2=br2.readLine())!=null)
       		{
         	list2.add(line2);
          	//System.out.println(list2);
        	}

                for(int i=0;i<list1.size();i++)
                 {
                  for(int j=0;j<list2.size();j++)
                   {
                     if(list1.get(i).equals(list2.get(j)))
                       {
                      list_similar.add(list1.get(i));
                       list1.remove(i);
                       
                       }
                     else
                       {
                       list_disimilar.add(list1.get(i));
                       list_disimilar.add(list2.get(j));
                        }
                    
                    }
                  }
       		System.out.println(list_similar);
                System.out.println(list_disimilar);
               
       }
     catch(FileNotFoundException e)
       {
         System.out.println(e);
         }
     
     }
}

can anyone please give me a lead to solve this problem

[Norm]

One way to see if the contents of one file is in the other file is to use a hashtable. Read all of one file into the hash table and then read the other file and ask the hashtable if it has that record.
Use the value part of stored data in the hashtable to keep track of the number of matches found. At eof on the second file, get all the values in the hashtable and see which ones had matches or not.


Could you put some comments in your code showing your logic?
If you sorted the list of records saved in the arrays, you could do something like a merge in your nested loop to compare the contents of one array with another.

What problem are you having? Copy and post error messages here.

[Ms.Ranjan]

this is the output i am getting..i could get the similar contents

[ename eid evalue, P 02 P637]

but for dissimilar contents i get this..

[S 01 S425, P 02 P637, S 01 S425, E 04 E738, S 01
S425, D 05 D369, P 02 P637, ename eid evalue, C 03 C826, E
04 E738, C 03 C826, D 05 D369]

i know the problem is with the logic..i am not able to figure this out..i am working on it..but if u have any other suggestion please kindly let me know..

[Norm]

Don't understand what the output you posted means.
it looks like the contents of some arrays, but there are no comments with it to describe what they are.
Add a coment to the println("NOT FOUND: " + array); etc
Simplify the problem by shortening the input files to 2 records each. For example:
File 1)
Same1
diff1
File 2)
Same1
diff2
Then add enough println() statements to your code to see exactly how it is processsing each record. From that you should be able to see what is going wrong.

[Ms.Ranjan]

Thanks Norm i will do that..your Hashset idea seems to be working..i am working on it....