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  1. 12-14-2011, 02:26 AM #1
    bhavinragha
    bhavinragha is offline Member
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    Post simple form & Servlet help

    i have a form
    Name:"name"

    and my servlet should output
    helloname

    i know there is an error in line 39 in my servlet class ploz help

    XML Code: 
    <html>
    <head>
        <title></title>
        <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
    </head>
    <body>
		<h1>A simple web application</h1>
		<form method="POST" action="HelloWorldServlet">
			<label for="name">Enter your name </label>
			<input type="text" id="name" name="name"/><br><br>
			<input type="submit" value="Submit Form"/>
			<input type="reset" value="Reset Form"/>
		</form>
	</body>

</html>
    Java Code: 
    import javax.servlet.annotation.WebServlet;
import java.io.IOException;
import java.io.PrintWriter;
 
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
 
/**
 *
 * @author eeua9b
 */
@WebServlet(name = "HelloWorldServlet", urlPatterns = {"/HelloWorldServlet"})
public class HelloWorldServlet extends HttpServlet {
  
    /** 
     * Processes requests for both HTTP <code>GET</code> and <code>POST</code> methods.
     * @param request servlet request
     * @param response servlet response
     * @throws ServletException if a servlet-specific error occurs
     * @throws IOException if an I/O error occurs
     */  
    
    protected void processRequest(HttpServletRequest request, HttpServletResponse response, String name)
            throws ServletException, IOException {
        String POST = request.getParameter("name");
        
        response.setContentType("text/html;charset=UTF-8");
        PrintWriter out = response.getWriter();
        try {
            // TODO output your page here
            out.println("<html>");
            out.println("<head>");
            out.println("<title>Servlet HelloWorldServlet</title>");  
            out.println("</head>");
            out.println("<body>");
            out.println("<h1>Servlet HelloWorldServlet at " + request.getContextPath () + "</h1>");
            //out.println("<h2>Hello " + name + "</h2>" );
            out.println("</body>");
            out.println("</html>");
             
        } finally {            
            out.close();
        }
    }

    // <editor-fold defaultstate="collapsed" desc="HttpServlet methods. Click on the + sign on the left to edit the code.">
    /** 
     * Handles the HTTP <code>GET</code> method.
     * @param request servlet request
     * @param response servlet response
     * @throws ServletException if a servlet-specific error occurs
     * @throws IOException if an I/O error occurs
     */
    @Override
    protected void doGet(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {
        processRequest(request, response);
    }

    /** 
     * Handles the HTTP <code>POST</code> method.
     * @param request servlet request
     * @param response servlet response
     * @throws ServletException if a servlet-specific error occurs
     * @throws IOException if an I/O error occurs
     */
    @Override
    protected void doPost(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {
        processRequest(request, response);
    }

    /** 
     * Returns a short description of the servlet.
     * @return a String containing servlet description
     */
    @Override
    public String getServletInfo() {
        return "Short description";
    }// </editor-fold>
}
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  2. 12-14-2011, 09:43 AM #2
    Tolls
    Tolls is offline Moderator
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    Default Re: simple form & Servlet help

    And the error is?
    Or are we supposed to guess...
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  3. 12-28-2011, 08:58 AM #3
    pala
    pala is offline Member
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    Default Re: simple form & Servlet help

    What is the error?
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  4. 01-04-2012, 01:42 PM #4
    vinci123
    vinci123 is offline Member
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    Default Re: simple form & Servlet help

    i cant figure out the error in this program
    I can and I will
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  5. 01-27-2012, 07:42 PM #5
    HowardHyde
    HowardHyde is offline Member
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    Default Re: simple form & Servlet help

    If you UN-comment line 39, you will get a compiler error on an undeclared variable 'name'. If you replace that line with
    out.println("<h2>Hello " + POST + "</h2>" );
    ...then it should work, because of line 27:
    String POST = request.getParameter("name");

    I recommend changing line 27 to
    String name = request.getParameter("name");
    and then line 39 will work fine as is.

    By convention, variable names are given in camelCase with leading lower-case letters; ALL_UPPER_CASE would normally be used for a final/constant value.

    Howard Hyde, author, 'Java Web Database Application Development' (JavaWebDB.com).
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