Hibernate subclasses

[Ed]

I want to map a subclass but I can't do it

the employee is a SUBCLASS of contact

Code:

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">

<hibernate-mapping>
   <class name=" entity.Contact" table="contact" >
      <id name="id_contact"  column="id_contact" unsaved-value="0">
         <generator class="identity"/>
      </id>
        <property name="name" column="name" type="string"/>
        <property name="lastname" column="lastname" type="string"/>
        <property name="address" column="address" type="string"/>
        <property name="city" column="city" type="string"/>
        <discriminator column="contact"/>
     <subclass name="entity.Employee" discriminator-value="B">
   
    </subclass>
    </class>
</hibernate-mapping>

the error is

Code:

688  [main] ERROR org.hibernate.util.XMLHelper  - Error parsing XML: XML InputStream(26) 
The content of element type "class" must match "(meta*,subselect?,cache?
,synchronize*,(id|composite-id),discriminator?,(version|timestamp)?,
(property|many-to-one|one-to-one|component|dynamic-component
|properties|any|map|set|list|bag|idbag|array|primitive-array|query-list)*,
((join*,subclass*)|joined-subclass*|union-subclass*),loader?,sql-insert?
,sql-update?,sql-delete?,filter*)".

do you know what is the problem?

[bbq]

The problem is the order of the tags xml, that is the cause of the problem

[Heather]

bbq is right
El tag discriminator must be after the id. I send you the correct xml

Code:

<hibernate-mapping>
   <class name=" entity.Contact" table="contact" >
      <id name="id_contact"  column="id_contact" unsaved-value="0">
         <generator class="identity"/>
      </id>
<!-- HERE -->
        <discriminator column="contact"/>
<!--******** -->
        <property name="name" column="name" type="string"/>
        <property name="lastname" column="lastname" type="string"/>
        <property name="address" column="address" type="string"/>
        <property name="city" column="city" type="string"/>
            <subclass name="entity.Employee" discriminator-value="B">
   
    </subclass>
    </class>
</hibernate-mapping>