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Unbounded Wildcards with Generics

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by , 11-29-2011 at 11:09 PM (2446 Views)
When you as a programmer decide to use an unbounded wildcard <?>, it appears to mean anything. and so using an unbounded wildcard seems equivalent to using a raw type. There are time that the compiler is indifferent as to using raw type or <?>. If you use <?> it can be considered as a decoration. When you are using the raw type, the generic parameter can hold any type. In this example I show an important use of unbounded wildcards. If you are dealing with multiple generic parameters, itís best to allow one parameter to be any type if possible, while establishing a particular type for the other parameter:

Java Code:
import java.util.*;

public class WildcardExample { 
   static Map map1; 
   static Map<?,?> map2; 
   static Map<String,?> map3; 
   static void assign1(Map map) { map1 = map; } 
   static void assign2(Map<?,?> map) { map2 = map; } 
   static void assign3(Map<String,?> map) { map3 = map; } 

   public static void main(String[] args) {
      assign1(new HashMap()); 
      assign2(new HashMap()); 
      assign1(new HashMap<String,Integer>()); 
      assign2(new HashMap<String,Integer>()); 
      assign3(new HashMap<String,Integer>());
   } 
}
So using wildcards allows you to accept a wide range of parameterized types as arguments. The question is which trade-off is best for your needs depending on the context.

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