Can't convert java.lang.String to int.

[Albert]

Hi could you help me this script. I got a error I don't know why.
I can't run this code

Code:

import javax.swing.JOptionPane;
public class Ito {
 public static void main(String[] args)
 {

  int number = JOptionPane.showInputDialog("Enter number: ");
  switch(number)
  {
    case 0:
         System.out.println("you typed zero");
         break;
    case 1:
     System.out.println("you typed one");
         break;
    default:
          System.out.println("you didn't type zero or one");
         break;


     }

     System.exit(0);

     }}

Here is error:

Code:

A:Ito.java:7: Incompatible type for declaration. Can't convert java.lang.String to int.
  int number = JOptionPane.showInputDialog("Enter number: ");
      ^
1 error

Tool completed with exit code 1

Could you help me.
Thanks
Albert

[susan]

The error message says it all. The showInputDialog method returns a string so you cannot assign it to an integer datatype. What you would need to do is convert it to an integer first.

Code:

import javax.swing.JOptionPane;
public class ito
{
 public static void main(String[] args)
 {

String input = JOptionPane.showInputDialog("Enter number: ");

int number = Integer.parseInt(input); 

  switch(number)
  {
    case 0:
         System.out.println("you typed zero");
         break;
    case 1:
     System.out.println("you typed one");
         break;
    default:
          System.out.println("you didn't type zero or one");
         break;

     }

     System.exit(0);

     }}

Of course it would probably be a good idea to add in some code to validate the input to ensure it actually is a number that they entered and also the required number of digits.

[satya123]

Code:

import javax.swing.JOptionPane;
public class Ito {
 public static void main(String[] args)
 {

String pn = JOptionPane.showInputDialog("Enter number: ");
int number=Integer.parseInt(pn);  

switch(number)
  {
    case 0:
         System.out.println("you typed zero");
         break;
    case 1:
     System.out.println("you typed one");
         break;
    default:
          System.out.println("you didn't type zero or one");
         break;


     }

 System.exit(0);

     }}

Now this code won't give that error i think....just parsed the returned string uing Integer.parseInt() wrapper class function.....