Quiz Time

[sukatoa]

Correct.... unsafe accessing....
If it is not a static, null exception occured.

Null.greet is a static method..........

[Eranga]

Ah, it's remember to me.

[rjuyal]

Quote:

Ah, it's remember to me.

Sorry Eranga, but i am not getting you!!

[Eranga]

What I'm saying is just without testing on an IDE, try to figure out the answer using what I have remember. It's work. Really nice to see that pal.

Oh, I love this thread.

[rjuyal]

Eclipse says,

Quote:

The static method ehem() from the type Null should be accessed in a static way

albeit answer is what you already said

[Eranga]

Wow, Eclipse give that much of explanation. ;(

[Eranga]

Here is the next quiz,

What is the output of following code. (No testing before answer

Code:

      for( ; ;) {
          System.out.println("Eranga");
      }

[rjuyal]

Code:

for( ; ;)

damn sure, it will go infinite for C, but in JAVA

should not compile, we need a boolean expression in 2nd place in For

Code:

for ( ; boolean_expression_here ; )

i guess, so?

[Eranga]

Anyone wants to try?

[Eranga]

Ok, it's not only in C. Give an infinite loop for Java as well.

[rjuyal]

easy questions should not be posted here
there should be some catches , after all it is a quiz section

[Eranga]

You think it's easy? One my friend repeat the exam because of this.

[rjuyal]

which xam u r talkin abt?

[Eranga]

University second year exam. We have to learn OOP on Java. At the final paper we got this as a one statement of a sample code. My friend don't know this gives a infinite loop, think there is a compile error. He lost 15 marks.

[rjuyal]

fifteeen maarks for dis quest lol

r u SCJP ?

[sukatoa]

Same rule,

If this is not a compilable code, why?
If this is, what's the output?

Code:

public class test extends B{

	public test(){
		this.printA();
		this.printB();
	}

	public static void main(String args[]){
		new test().printA();
	}
}

abstract class B extends A{
	public void printA(){
		System.out.println("class B");
	}		
}

abstract class A{
	public void printB(){
		System.out.println("class A");
	}
}

[rjuyal]

class B
class A
class B
????

[Jesdisciple]

*IF* it's compilable, the output would be

Quote:

class B
class A
class B

EDIT: Looked at it again, changed my code, you trickster...

But I think the compiler would complain that "Class B cannot be found" or something to that effect.

[Eku]

class A

^_^

[Eranga]

Code:

class B
class A
class B

I agreed with Rakesh.

First two lines from the constructor call. Then from the main method.

Did you found any unsecured thing here in that code?