Quiz Time

[Eranga]

Yes pal. Ternary operator become false there.

[Eranga]

Quote:

Originally Posted by rjuyal

BTW, what's the logic behing 2.3

i will post the answer with reason after this

I didn't get you on this pal.

[rjuyal]

Code:

Value will be 2

sanjeev please post the exact print

like Eranga did

Code:

Value is - 2.3

You want the answer ??

[Eranga]

I'm worried on my last post Rakesh. What you mean the logic of 2.3, any special reason.

May be your answer give the solution.

[sanjeevtarar]

Code:

Value is - 2

[rjuyal]

answer is

Code:

Value is: - 2.0

Reason being

a>5 evaluates to false so the answer should be

Code:

Value is: - 2

but,

2.3 ( double) and 2(int) are of different types. So the type chosen by Ternary will be by rule of promotion, hence 2 will be converted to 2.0

and the answer is

Code:

Value is: - 2.0

[sukatoa]

it should be 2.... i think....

5 never can be called greater than 5......

[sanjeevtarar]

Quote:

Originally Posted by Eranga

I'm worried on my last post Rakesh. What you mean the logic of 2.3, any special reason.

May be your answer give the solution.

Actually he is asking that, How you got this ans, What is your logic to calculate the 2.3.

[Eranga]

Ah, a nice point. ternary operator evaluates integer values.

Anyway, I have to go now my friends. Keep going, I'll back to here tomorrow. Nice work pal. Thanks for all of you. Keep going this, rather starting a new one. Doesn't matter how it long. I'll manage i'll manage it for all of you.

Good luck,
Eranga

[rjuyal]

answered in #66

Next question Please

[sukatoa]

Code:

public class test{
       public static void main(String quiz[]){
              String t1 = "23";
              String t2 = "11.5 * 2";
              if(Double.valueOf(t1)==Double.valueOf(t2))
                     System.out.print("true");
              else
                     System.out.print("absolutely impossible");
       }
}

What can you guess about the code above?

[rjuyal]

parse exception

[sanjeevtarar]

Number Format Exception...

[sukatoa]

Yah... NumberFormatException.....

It can never be treat as a pure Floating Decimal values.
...11.5 * 2...

[sukatoa]

Without attempting to compile the code below,

What should be the output?

Code:

public class test {

    public static void main(String quiz[]) {

        System.out.print("H" + "a");

        System.out.print('H' + 'a');

    }

}

[sanjeevtarar]

Quote:

Originally Posted by sukatoa

Without attempting to compile the code below,

What should be the output?

Code:

public class test {

    public static void main(String quiz[]) {

        System.out.print("H" + "a");

        System.out.print('H' + 'a');

    }

}

Will not compile

[sukatoa]

Actually it compiles.... it has an output. guess what?

[sukatoa]

at first attempt of printing "Ha", allowable... obviously,

The problem is on the second attempt....
H and a are now char literals... There decimal value will be printed.. instead of concatenating like the previous one, it now adds their decimal representation that leads to 169

eg. Ha169.

ref, ascii chart.

Just sharing,

[rjuyal]

o man! i could have answered it

y i got the mail notification after half an hour

[sukatoa]

maybe because you have subscribed a specific thread.

next quiz please... i hope i can catch one....