Quiz Time

[rjuyal]

correct!


long variable cannot be used as array index, only integer is accepted

[sanjeevtarar]

Will not compile....i think so

[sanjeevtarar]

One from my side
Will this compile..??if yes...Output

Code:

public class TestQue 
{
	public static void main(String[] args) 
	{
		int j; 
		for(int i=0;i<14;i++) { 
			if(i<10) { 
				j = 2 + i; 
			}
		}
		System.out.println("j: " + j + " i: " + i); 
	}
}

[Eranga]

Quote:

Originally Posted by rjuyal

correct!


long variable cannot be used as array index, only integer is accepted

I have to use the correct word too. INDEX.

[Eranga]

Quote:

Originally Posted by sanjeevtarar

One from my side
Will this compile..??if yes...Output

Code:

public class TestQue 
{
	public static void main(String[] args) 
	{
		int j; 
		for(int i=0;i<14;i++) { 
			if(i<10) { 
				j = 2 + i; 
			}
		}
		System.out.println("j: " + j + " i: " + i); 
	}
}

Out of bound

You have exceed the variable scope. How lucky I'm to find it. You can't use variable 'i' in println(). It's valid only within the for loop.

[sanjeevtarar]

Very good.....if we remove i from SOP....??

[sanjeevtarar]

Output..??..or..??

Code:

public static void main(String args[]) { 
 int total = 0; 
 int[] i = new int[3]; 
 for(int j=1;j<= i.length; j++) 
 total += (i[j] = j); 
 System.out.println(total); 
 }

[Eranga]

<=

ArrayOutOfBoundException at run time. Compiled is ok, runtime failed. Right?

[sanjeevtarar]

yes.............

[Niveditha]

Code:

public class TestQue 
{
	public static void main(String[] args) 
	{
		int j; 
		for(int i=0;i<14;i++) { 
			if(i<10) { 
				j = 2 + i; 
			}
		}
		System.out.println("j: " + j + " i: " + i); 
	}
}

Quote:

Very good.....if we remove i from SOP....??

Compilation Error: "j" not initialized correct?

[Eranga]

Yep, that's right. But compile and try, that error get if the scope error is fix.

[rjuyal]

xcuse to wake you again..

will it compile, if yes then what will be the output.

--

Code:

public class InheritanceTest {
	
	public static void main(String[] args) {		
		Base base = new Child();
		base.fun();
		base.fun2();		
	}

}

class Base{
	public void fun(){
		System.out.println("Fun in Base");
	}
	public static void fun2(){
		System.out.println("Fun2 in Base");
	}
}

class Child extends Base{
	public void fun(){
		System.out.println("Fun in Child");
	}
	public static void fun2(){
		System.out.println("Fun2 in Child");
	}	
}

---------

[dlorde]

If you like Java puzzles, this'll kill you ;-)

What's the output ?

Code:

public static void main(String[] args) {

    Integer i1a = Integer.valueOf(124);
    Integer i1b = Integer.valueOf(124);

    Integer i2a = Integer.valueOf(133);
    Integer i2b = Integer.valueOf(133);

    System.out.println("i1a == i1b : " + (i1a == i1b));
    System.out.println("i2a == i2b : " + (i2a == i2b));
}

[dlorde]

rjuyal, static methods belong to the reference type, non-static methods belong to the instance type.

[Eranga]

Quote:

Originally Posted by rjuyal

xcuse to wake you again..

will it compile, if yes then what will be the output.

--

Code:

public class InheritanceTest {
	
	public static void main(String[] args) {		
		Base base = new Child();
		base.fun();
		base.fun2();		
	}

}

class Base{
	public void fun(){
		System.out.println("Fun in Base");
	}
	public static void fun2(){
		System.out.println("Fun2 in Base");
	}
}

class Child extends Base{
	public void fun(){
		System.out.println("Fun in Child");
	}
	public static void fun2(){
		System.out.println("Fun2 in Child");
	}	
}

---------

Nice to see that we are moving with this again after a long time.

Ok, for me this code segment is compiling and the output is,

Quote:

Fun in child
Fun2 in base

What you say pal,

[Eranga]

Quote:

Originally Posted by dlorde

If you like Java puzzles, this'll kill you ;-)

What's the output ?

Code:

public static void main(String[] args) {

    Integer i1a = Integer.valueOf(124);
    Integer i1b = Integer.valueOf(124);

    Integer i2a = Integer.valueOf(133);
    Integer i2b = Integer.valueOf(133);

    System.out.println("i1a == i1b : " + (i1a == i1b));
    System.out.println("i2a == i2b : " + (i2a == i2b));
}

True/false validation with wrapper classes. So the output is,

Quote:

i1a == i1b : true
i2a == i2b : false

Because you exceed the NUMBER 127 there. Hops you got the point.

[rjuyal]

@Eranga ,
correct answer of my question.

can you elaborate the answer of previous question

Quote:

Because you exceed the NUMBER 127 there. Hops you got the point.

[Engineeringserver.com]

After reading the thread i'm itching to write my own test quiz and test if anyone can solve it =) Anyway, you could also read the book "java puzzlers" it contains many questions and some of the answers might be what you wouldn't expect.

[Eranga]

Quote:

Originally Posted by rjuyal

@Eranga ,
correct answer of my question.

can you elaborate the answer of previous question

First of all sorry for the late replay. So here we got a nice thread to discuss. Lets have a fun pal.

At the time, change 124 to 127 and, 133 to 128 and run the code. What you get? Confusing?