Responses from UDP Server

[Mnelson]

Hi Ive made the following program I'm just looking for a little help on how to fix the following:

1)I'm stuck trying to figure out how to supply the listening port number as a command line argument when starting the program.
)For example I want it to ask for a port number when I start the program and use that specified port.

2)The second thing im trying to do is have the server report back a string that tells the client how many integers and non-integer words were in the previous message.
)For example I send the following message from my client to my server "Hi today is July 6"
I want my server to return a string "4 1"
Indicating that the incoming string has 4 non integer words and 1 integer.

Here is my code.

 public static void main(String[] args) throws Exception
{
int kimbo= 1;
DatagramSocket serverSocket = new DatagramSocket(4567);
InetAddress myIp =InetAddress.getLocalHost();
byte[] receiveData = new byte[1024];
byte[] sendData = new byte[1024];
System.out.println("Using port: " + serverSocket.getLocalPort() );
System.out.println("IP: " + myIp.getHostAddress() );
while(kimbo== 1)
{
DatagramPacket receivePacket = new DatagramPacket(receiveData, receiveData.length);
serverSocket.receive(receivePacket);
String Str= new String(receivePacket.getData());
if(Str.contains("1"))
{

System.out.println("The received string was: " + Str);
InetAddress IPAddress = receivePacket.getAddress();
int port = receivePacket.getPort();
String capitalizedSentence = line.toUpperCase();
sendData = capitalizedSentence.getBytes();
DatagramPacket sendPacket = new DatagramPacket(sendData, sendData.length, IPAddress, port);
serverSocket.send(sendPacket);
}
else if(Str.contains("2"))
{
DateFormat dateFormat = new SimpleDateFormat("MM/dd/yyyy HH:mm");
Calendar cal = Calendar.getInstance();
System.out.println("The received string was: " + Str);
InetAddress IP2 = receivePacket.getAddress();
int port2 = receivePacket.getPort();
String time = dateFormat.format(cal.getTime());
sendData = time.getBytes();
DatagramPacket sendPacket2 =
new DatagramPacket(sendData, sendData.length, IP2, port2);
serverSocket.send(sendPacket2);
}
else
{
System.out.println("The received string was: " + Str);
System.out.println("Exiting");
kimbo =0;
}

[Tolls]

You need to indent your code.
That's hard to follow as it stands.

Anyway, for (1):
java <yourapp> 1234

public static void main(String[] args) {
    String port = args[0];
    // port will be == 1234 here.
}

You'll want to stick the usual check that you have some args supplied if they are supposed to be mandatory, or prompt at that point.

[Mnelson]

Sorry about that! So would this work?


public static void main(String[] args) throws Exception
{
int Part = 1;
String port = args[0];
DatagramSocket serverSocket = new DatagramSocket(port);

InetAddress myIp =InetAddress.getLocalHost();
byte[] receiveData = new byte[1024];
byte[] sendData = new byte[1024];
System.out.println("Using port: " + serverSocket.getLocalPort() );
System.out.println("IP: " + myIp.getHostAddress() );
while(Part == 1)