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Thread: Nested For Loop algorithm
 01082011, 11:03 PM #1Member
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Nested For Loop algorithm
Hi guys.
My head is gone tonight and I hoped someone would help me to solve this Nested for loop algorithm.
Basically what I want is nested for loop that would sort an array of numbers like this:
12345678
22345678
33345678
44445678
55555678
66666678
77777778
88888888
Any help would be appreciated.
 01082011, 11:17 PM #2Senior Member
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you can do your own sort routine using one of many sort algorithm, or you can use Arrays/(collections) which have the sort() method.
 01092011, 02:35 PM #3
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What is there to be sorted? If the top left corner has coordinate (0, 0) (x moving to the right, y moving downwards in their positive directions) the value in each grid cell is Math.max(x+1, y+1). Simply fill in each cell with those values and you're done.
kind regards,
Joscenosillicaphobia: the fear for an empty beer glass

Also, to the OP, it's always best to show your most recent attempt at a solution when asking these types of questions.
 01112011, 06:44 AM #5Member
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The solution is below, but before you look at it, think about it first.
How many times are you printing the first number of each line?
Are there any patterns?
I had this problem about a few months ago too, but it really shouldn't be that much of a challenge. Try to code it before looking at the solution below :)
Java Code:for(int x = 1; x <= 8; x++){ for(int y = 1; y <= 8; y++){ if (y<=x) array[x][y] = x; else array[x][y] = y; } }
Last edited by themulator; 01112011 at 06:47 AM.
 01112011, 09:52 AM #6Moderator
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