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Thread: Nested For Loop algorithm
 01082011, 11:03 PM #1Member
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Nested For Loop algorithm
Hi guys.
My head is gone tonight and I hoped someone would help me to solve this Nested for loop algorithm.
Basically what I want is nested for loop that would sort an array of numbers like this:
12345678
22345678
33345678
44445678
55555678
66666678
77777778
88888888
Any help would be appreciated.
 01082011, 11:17 PM #2Senior Member
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you can do your own sort routine using one of many sort algorithm, or you can use Arrays/(collections) which have the sort() method.
 01092011, 02:35 PM #3
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What is there to be sorted? If the top left corner has coordinate (0, 0) (x moving to the right, y moving downwards in their positive directions) the value in each grid cell is Math.max(x+1, y+1). Simply fill in each cell with those values and you're done.
kind regards,
JosThe only person who got everything done by Friday was Robinson Crusoe.

Also, to the OP, it's always best to show your most recent attempt at a solution when asking these types of questions.
 01112011, 06:44 AM #5Member
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The solution is below, but before you look at it, think about it first.
How many times are you printing the first number of each line?
Are there any patterns?
I had this problem about a few months ago too, but it really shouldn't be that much of a challenge. Try to code it before looking at the solution below :)
Java Code:for(int x = 1; x <= 8; x++){ for(int y = 1; y <= 8; y++){ if (y<=x) array[x][y] = x; else array[x][y] = y; } }
Last edited by themulator; 01112011 at 06:47 AM.
 01112011, 09:52 AM #6Moderator
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