Running java program with arguments in Unix"

[gvi]

Hi
I am a new newbie to java so pardon if this is too simple for you .

This is my scenario. I have a java program which parses an xml and writes a .dat file. I execute this testparser.java in unix environment like this

java testparser xml1.xml

and it retuns me a .dat file

But my issue is I have to run my parser program for 40 xml files. The requirement is I have to create a script file and possibly with a for loop which will loop through 1-40 xml files and return me the .dat file.

I am really at a loss here. I am new both to Java and Unix

So pls help me out

Thanks in Advance
G

[JavaBean]

What about creating a text file which will have your xml files listed in separate lines. As far as i understand your problem, you can modify your program to get this .txt file as an input and loop for all these xml files to generate dat file(s).

[made.putrama]

You may try the following code:

public class TestParser{
	public static void main(String[] args){
		for(int i=0; i<Integer.parseInt(args[1]); i++)
		{
			File file = new File(args[0]+"/filename"+(i+1)+".xml");
			doTestParser(file);
		}
	}
	
	static void doTestParser(File pFile ){
		//do something with the xml file
	}
}

You should now execute only one time from the command line, e.g:

/>java Testparser <<file directory>> <<total file>>


Regards,
Putrama