How to count charectors in string?

[satheeshtech]

Hi all,
I have a String object like String s="Hello";
Here how to program to count occurences of each character?

Need output like
H - 1time,
l -2 times ,etc..

[PhHein]

In how many more forums are you going to post that same question?

[JavaJuJitZu]

Now assume do it without the String libraries and assume the string is a c string.

[Supamagier]

Now assume do it without the String libraries and assume the string is a c string.

What's the use of that? It's a Java forum

[satheeshtech]

hi satheesh.,
i could not get your code yar... can you explain it pls

[r035198x]

hi satheesh.,
i could not get your code yar... can you explain it pls

Why did you abandon your other thread?

How to count occurences of charectors in string?

Was it because you were asked to write the code for a change?

[PhHein]

Why did you abandon your other thread?

How to count occurences of charectors in string?

Was it because you were asked to write the code for a change?

You didn't spoon feed him. In this thread he at least got useless code.

[collin389]

I'm pretty sure I read a java tutorial on this on Sun's website. If you are looking for code, it might be there.
Nvm, found it.

import java.util.*;

public class Freq {
    public static void main(String[] args) {
        Map<String, Integer> m = new HashMap<String, Integer>();

        // Initialize frequency table from command line
        for (String a : args) {
            Integer freq = m.get(a);
            m.put(a, (freq == null) ? 1 : freq + 1);
        }

        System.out.println(m.size() + " distinct words:");
        System.out.println(m);
    }
}

From The Map Interface (The Java™ Tutorials > Collections > Interfaces)

[r035198x]

I'm pretty sure I read a java tutorial on this on Sun's website. If you are looking for code, it might be there.
Nvm, found it.
...

Nothing the OP doesn't have to do anything.
Was better to let the OP learn better by trying it themselves first.

[collin389]

I think it's was pretty obvious that the OP doesn't want to learn and just wants the code(since he started 2 threads asking for "just code"). Besides, hopefully there are parts he doesn't understand and will look those parts up.

[satheeshtech]

got the answer. thank u all

String text="satheesh";
text=text.toLowerCase();
int charNum=26; // the number of unique characters

int[] freq=new int[charNum];


for(int i=0;i<text.length();i++) {

freq[text.charAt(i)-'a']++;
System.out.println(text.charAt(i)-'a');
}

for(int i=0;i<charNum;i++) {
System.out.println("Frequency of " + (char) (97 + i) +": " + freq[i]);
}

[Tolls]

Or possibly he won't, will still get whatever worthless piece of paper as a qualification, write some utter rubbish in the real world, and I'll have to clean it up...

If he doesn't want to learn then don't give him the opportunity to pass!

[JosAH]

Or possibly he won't, will still get whatever worthless piece of paper as a qualification, write some utter rubbish in the real world, and I'll have to clean it up...

That's one of the reasons it's still such a mess in the ICT world: too many no-goods bluff their way into it, big mouth their way into some stolen/borrowed/copied code and turn everything into one big mess and others have to clean up after those people have gone again.

kind regards,

Jos