[revathi17]

There is actually a way to get the index..Arrays has a method
binarySearch(array to be searched,key) which returns the position of the specified key..
Using it in your program:

Code:

import java.util.*;
public class LargestNo{
	public static void main (String [] arg) {
	
		Scanner scan = new Scanner (System.in);
		
		int [] numbers = new int [3]; 

		int x; 
		int largestNumber; 
		//int pos=0;//position in the array
		int index=0;
		
		System.out.print("Put in (three) numbers");
		for (x=0; x<numbers.length; x++) {
			numbers[x]=scan.nextInt ();
		}
		
		largestNumber = 0; 
		
		for (x=0; x<numbers.length; x++) { 
		if (x == 0) {
		    largestNumber = numbers[0];
		    //pos = 0;
		}
		if (numbers[x] > largestNumber) {
		    largestNumber = numbers[x];
		    //pos = x;//x is the position of the number in the array.
		   index = Arrays.binarySearch(numbers, largestNumber);
		}
		}	
		System.out.println("The largest number is " + largestNumber);
		System.out.println("Position of the largest number:"+index);
	
	}
}

I am not sure though if this would be a correct way to get the index of an array element...


Thanks,
R