[rjuyal]

Eranga absolutely correct!

actually on compilation, the code will be converted to this,

Code:

public class ObjectTest  {	
	ObjectTest myObject;

     ObjectTest ()
     {
         myObject = new ObjectTest();
      }
	
	public static void main(String[] args) {		
		ObjectTest myObject = new ObjectTest();
		System.out.println(myObject);
	}	
}

Hence the answer, STACK OVERFLOW

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