hi sanjeev
i will give u a clear idea
think in
array al1={1,2}
array al2={1,2,3,4,5,6,7,8,9,10,11,12}
Now what i have to do is
if (al1(elements)==compare al2(only4 elements 1,2,3,4))
{
/*continues my logic*/
}
else if (al1(elements)==compare al2(only4 elements)ie 5,6,7,8)
{
/*continues my logic*/
}
else if (al1(elements)==compare al2(only4 elements)ie 8,9,10,11,12)
{
/*continues my logic*/
}
the above output of comparing the two arrays i need in two for loops then the CODE will be
MY CODE:
array al1={1,2}
array al2={1,2,3,4,5,6,7,8,9,10,11,12}
int arrayList1_Length = al1.size();
int arrayList2_Length = al2.size();
for (int i=1;i<arrayList2_Length;i++) {
for (int j=1;j<arrayList1_Length; j++) {
{
}}
}
In my code all the values of all are comparing with all the elements of al2.
This is not what i need.
I need to be compare everytime with all the elements of al1 and only 4 elements of array2 (upto the end of all the elements of array al2 )
that means al1 will be constant
al2 will be looping for every 4 elements
think that there were 12 elements in al2, so 4 times the inner loop will move
i need the code in the loops
NOTE: DONOT CONSIDER WHETHER THE ELEMENTS WERE MATCHABLE OR NOT, ONLY WE HAVE TO COMPARE THE VALUES ACCORDING TO THE NO OF ELEMENTS , I WILL WRITE MY OWN LOGIC ISIDE THE LOOPS
ANY QUERIES REPLY ME BACK .