[xfrag]

Well I'm not sure I understood correctly what are you trying to do, but I can help you find the zeros. Use the following code:

Code:

try {
    Pattern p = Pattern.compile("0{2,}");
    Matcher m = p.matcher("11135781222111122330000000000000000000000000000000 00000");
    int idx = -1;
    String output = "";
    while (!m.hitEnd() && m.find()) {
            if(idx == -1){
                idx = m.start();
            }
            output += m.group();                    
    }
    if(output.length() >= 35){
           System.out.println("Found 35 consecutive zeros:");
           System.out.println(output.substring(0,35));
           System.out.println("Start index: " + idx);
    }
            
} catch (Exception matchEx) {
            System.out.println(matchEx.getMessage());
}

This way you also have the index of the fist zero in the sequence, so you can get the "n-th" characters you're looking for, append them at the front of the output, add spaces where needed and you're done!

Note: I don't know if ALL your requirements can be met using a single regular expression, and I think they cannot.