[michcio]

here is my code ones again (without any errors now):

Code:

    public static void main(String [] arg){
        String a = JOptionPane.showInputDialog("Skriv in ett ord!");
        int b = 0;
        int c = a.length()-1;     //root's sugeston works perfectly!!
        String ord1 = "";
        String ord2 = "";
        for(int d=0; c<b; d++){
            ord1 = ord1 + a.substring(b,(b+1));
            ord2 = ord2 + a.substring(c,(c+1));
            c--;          
            b++;           
        }
        if(ord1.equals(ord2))
            JOptionPane.showMessageDialog
                    (null, "Det inskrivna ordet är ett palindrom!!!");
        System.exit(0);
    
        

  
    }

Quote:

Originally Posted by CaptainMorgan

Are you absolutely sure?

yeah I am absloutly sure...but I have found the error myself now... The length()-1 was helpfull I didn't knew that if you had a word for ex. "hello" then the length of it was 5 and not 4. But there was one more error in this program. In the "for" loop I have written !(b==c) (have now been change in the program see the red boolean) and it means that when b ins't equals to c the "for" loop runs. This works but only if the word have odd numbers of letter in it for example it works fine when I write the word "hello" because first b=0 and c=length()-1 gives c=4 ...the for loop runs and c gets 3 and b = 1 again ...c become 2 and b = 2 ... the loop ends (b==c!!!!!) but if I write a word with even numbers ofletter it doesn't work. For example "ha" b=0 and c=1...the for loop runs ones and b become 1 and c 0... and so on ... (c never become equals to b!!!) String gets out of expression !!! ... Therefor I should instead chande !(b==c) to c<b (red in the program) so the program works both for odd and even numbers of letters in a word...
So my problem is now sulved... and tanks a lot for your help

Michcio